Friday, May 9, 2014

Practical 1

PRACTICAL 1
Title : Phase diagram for ethanol/toluene/water system

Objective : To determine the phase diagram for ethanol/toluene/water system theory

Introduction :

    In three-component system at constant temperature and pressure, the composition can be expressed in coordinates form of triangular diagram
                                                                        A



 





 



 




Figure 1 : Ternary Phase Diagram.

    In the above diagram, each corner of the triangle represent one pure component, that is 100 %A, 100%B and 100%C. Each side of the triangle represent two-component mixture and in this triangle represent ternary component. Any line that is parallel with one side of the triangular diagram show the constant percentage value for a component, such as DE show 20%A with any amount of B and C. Line FG also show all mixture consists of 50%B. These lines intersect at K which contains 20%A, 50%B and 30%C. Measurement can be made like this, it is because sum of all the distance from K which draw parallel to the three sides of the triangle are the same and equal length with anyone from the side the triangle in the triangular diagram.

    Addition of the third component to one pair liquid-liquid which is miscible can change the solubility of them. If the third component is more soluble in one of these two component, solubility of both liquid will decrease, but if it is soluble in both component, their solubility will increase. Hence when ethanol is added to one mixture of benzene and water, solubility of these two component will increase until achieve a point where this mixture  become homogeneous. This method is used in formulation of liquids. Examples of 3 liquids component system which had been tested include castol oil/alcohol/water ;”minyak permen”/glycol propylene/water, “minyak permen”/glycol polyethylene/water.

     Advantage in preparing an oily ingredient as a homogeneous liquid aqueous is very obvious. However, we need to know what will happen to a system like this when it is diluted and this can be explained through the understanding of the triangular phase diagram. Figure 1 is for system and components of “minyak permen”polysorbate20-water. One concentration of 7.5%oil, 42.5% of polysorbate 20 and 50% of water ( point A in diagram) can be diluted for  10 times with water, giving one clear solution ( still having 0.75% oil, 4.25% polysorbate 20 and 95% of water )  However, when 1mL of water is added to 10mL: of clear solution B ( 49% oil, 50% polysorbate 20,1%water) solution becomes cloudy, point B’(44.5% oil, 45.45% polysorbate 20 and 10 %water). If add 1mL of water continuously, solution will become clear, point  B’’ ( 40.5% oil,41.3% polysorbate 20, 18.2%water) but the original solution if have been dilutied 3 times ( 16.33% oil, 16.33% polsorbate 20, 67.33 % water) solution becomes cloudy.

Chemicals :
Ethanol, toluene and distilled water

Apparatus
Conical flask, conical flask stopper, retort stand and clamp, pipette, and burette.


Procedures:

1. Mixtures of ethanol and toluene which containing percentages of ethanol : 10, 25, 35, 50, 65, 75, 90 and 95 were prepared in a 100 cmclosed conical flask.

2. 20mL of each mixture was prepared by adding the needed volume of solution using a burette to obtain an accurate volume.

3. The pipette was filled with water.

4. Each of the mixture was titrated with the water until a cloudy solution formed result from the formation of two phase system.

5. Water was added drop by drop and the conical flask was shaken vigorously after each addition.

6. The volume of water used for each titration recorded.

7. The percentage according to the volume of each component when the two phase       system observed was calculated.

8 The point was plotted in the triangular coordinate graph paper.

9. The experiment was repeated again to obtain more accurate result.


Results :


Percentage of ethanol (%)
 Volume of ethanol(mL)
Volume of toluene (mL)
Volume of water used(mL) in 1st test
Volume of water used(mL) in 2nd test
Average volume of water used (mL)
10
25
35
50
65
75
90
95
2.0
5.0
7.0
10.0
13.0
15.0
18.0
19.0
18.0
15.0
13.0
10.0
7.0
5.0
2.0
1.0
0.5
0.8
1.0
1.8
3.0
4.6
10.8
15.8
0.6
0.7
1.1
2.2
3.4
4.8
11.0
16.2
0.45
0.75
1.05
2.20
3.20
4.70
10.9
16.0




Total volume of mixture(mL)
Ethanol

Volume     Percentage
     (mL)          (%)
Toluene

Volume      Percentage
    (mL)          (%)
Water

Volume        Percentage
(mL)             (%)
20.45
20.75
21.05
22.20
23.20
24.70
30.90
36.00
         2.0             9.8
5.0           24.1
7.0           33.3
10.0          45.0
13.0          56.0
15.0          60.7
18.0          58.3
19.0          52.8
18.0             88.0
15.0             72.3
13.0             61.8
10.0             45.0
7.0              30.2
5.0              20.2
2.0                6.5
1.0                2.8
   0.45                  2.2
   0.75                  3.6
   1.05                  4.9
   2.20                10.0
   3.20                13.8
   4.70                19.1
   10.9                35.2
   16.0                44.4




Diagram : Phase diagram of water-toluene-ethanol

Question :

1. Does the mixture containing 70%ethanol, 20% water and  10% toluene(volume) appear clear or does it form two layers?
The solution appear clear.

2. What will happen if 1 part of the mixture is diluted with 4 parts of (a) water (b) toluene (c) ethanol ?

Let assume that 1 part of solution = 100mL
So, 4 parts = 400mL

(a) Original volume :  70% ethanol = 70mL
                                    20% water    = 20mL
                                    10% toluene = 10mL (Total volume = 100mL)

After dilution with 400mL water
70%ethanol= 14%
20% water = 84%
10% toluene = 2 %    (Total volume = 500mL )

From the graph, the point A is inside two liquid phase, hence cloudy solution is formed



(b) Original volume :  70% ethanol = 70mL
                                    20%water  = 20mL
                                    10%toluene =10mL  (Total volume = 100mL )

After dilution with 400mL toluene
70%ethanol = 14%
20%water = 4%
10%toluene = 82%    (Total volume = 500mL )

From the graph, pint B is inside the two liquid phase, hence cloudy solution is formed



(c) Original volume :   70%ethanol = 70mL
                                     20%water = 20mL
                                     10%toluene= 10mL  (Total volume = 100mL )

After dilution with 400mL of 70%ethanol
70%ethanol = 94%
20%water= 4%
10%toluene= 2%    (Total volume = 500mL )

From the graph, point C is outside the two liquid phase, locating single, hence clear solution is seen


Discussion :

Phase diagram for ternary systems is usually represented using a triangle. Each of the three corners or apexes of the triangle represent 100% by weight of one component ( ethanol, water or toluene). As a result, that same apex will represent 0% of the other two components. The three lines which join the corner points represent two-component mixtures of the three possible combinations of ethanol, water and toluene. Therefore the lines ethanol-toluene, toluene-water, and water-ethanol are used for two component mixtures of ethanol and toluene, toluene and water, water and ethanol, respectively. The area within the triangle represents all the possible combinations of ethanol, toluene and water to give three-component systems.

In this practical,water and toluene are partially miscible, so when mixing usually forms two-phase system. The heavier of the two phases consists of water saturated with toluene, while the lighter phase is toluene saturated with water. However, ethanol is completely miscible with both toluene and water. It shows that addition of sufficient alcohol to two-phase system of water and toluene will produce a single liquid phase which make the three components miscible.

The result of this experiment has been plotted on a triangular diagram as shown in diagram 1. The curve plotted on the triangular diagram is known as the bimodal curve. The region below the curve represent a two phase system. The mixture found in this region are cloudy and there is an obvious separation of two phases. Although ethanol is miscible with both water and toluene, the immiscibility of water and toluene is more than the homogenous effect brought about by ethanol alone. Therefore,the amount of ethanol is insufficient to produce a homogenous one phase mixture. However the systems found in region above the curve are one phase systems. The amount of ethanol  in these systems enough to produce a homogenous mixture and a clear mixture is obtained for the systems found in this region.

Some experimental errors maybe happen in the experiment and cause inaccurate result formed. Firstly, when taking reading on burette , the eyes of observer maybe not parallel to the meniscus level of the water which caused reading of volume taken and recorded wrong. Secondly, the conical flask is not swirled well after each addition of water and this may result inaccurate volume of water was taken. Furthermore, judgment of cloudy solution formed depends on personal judgment as the cloudiness is not obviously seen.

Conclusion :
Ethanol, toluene and water system is a ternary system with one pair of partially miscible liquid( toluene and water).


Reference :
1) http://www.rpi.edu/dept/chem-eng/Biotech-Environ/DOWNSTREAM/ternary.htm
2) Physical pharmacy : Physical chemistry Principles in Pharmaceutical sciences, by    Martin A.N.
3) Physicochemical Principles of Pharmacy , 3rd edition (1998) . A.T. Florence and D.Attwood. Macmillan Press Ltd.





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